[PennyThePenguin]

hmm..i'm looking at it again it's the y that's got me stumped it looks calculus-ish. ah well. sorry preet

[Deboogle!.]

I don't like fish, Noelle, but I agree that it should be sugar-free

And yes, I do like Fish

Here you go Jiat

[PennyThePenguin]

mmmmmmmmm.....lecker

[andyroxmysox12191]

thanks for the help nat and roo
but nat....the answer is 2000 :S

[PennyThePenguin]

what answer's 2000?

[cath777]

Originally Posted by andyroxmysox12191

thanks for the help nat and roo
but nat....the answer is 2000 :S

Mani, use what Jiat did but P should be in thousands, so you start with P = 16,560 and then when you move this to the other side of the equation it become -9810 (=6750-16560). Solve this and you get 30, which added to 1970 gives 2000.

And, I'm lost on Q63 too. Do you have the formula to calculate a volume?

And, yes, I'm a total geek.

[PennyThePenguin]

woops. lol...i was thinking 2 millenia was kinda off target shows how great my maths is LMAO.

[Angle Queen]

Originally Posted by cath777

Mani, use what Jiat did but P should be in thousands, so you start with P = 16,560 and then when you move this to the other side of the equation it become -9810 (=6750-16560). Solve this and you get 30, which added to 1970 gives 2000.

And, I'm lost on Q63 too. Do you have the formula to calculate a volume?

And, yes, I'm a total geek.

Yep, I got that too. t=30 because P is in 1000s.

I'll take a look at 63. I'm guessing there are some derivatives involved as you have to determine a max and the area under the curve.

Another geek here too.

[PennyThePenguin]

yeah. i was thinkng it involved calculus. because u can't find the maximum of y just by solving the equation

[surfpinky]

SEND ME GOOD VIBES FOR MY FINAL!!!! please ):

[PennyThePenguin]

*send good vibes*

[Angle Queen]

*good vibes* *good vibes*

Now to problem 63.

To find 'maximum', you'll need the first derivative:

so if y = -0.0025x^2 + 1.25x, then the first derivative is:

y or 0 = (-0.0025*2)x + 1.25

Solving for x, yields:

0 = -0.005x + 1.25
-0.005x = -1.25
x = 250

Now, plug x = 250 into the equation to arrive at the maximum height.

y = -0.0025(250)^2 + 125(x)
y = -156.25 + 312.5
y(max) = +156.25

[Angle Queen]

Shall I go on? Or can you take it from here...with these hints:

"Width" is determined by 'solving' the equation.

"Volume" is determined by the 'area under the curve' (which should come from taking the integral between 0 and your 'width') multiplied by the depth (which looks to be 500 ft).

If you really want to get fancy and turn your answer in with how 'volume' would be expressesd on a real construction site, the solution should be in cubic yards (which is # of cubed feet divided by 27...or 3 cubed).

For example: 100 ft^3 = 3.7cy

And for what it's worth, a typical dump truck holds 10 cy.

(and I hope I'm right . It's been a looooong time.)

[PennyThePenguin]

ta daaaaa!!!!!!!!!!!!!!!!!!! calculus... *waits for deb to freak out now*

[Angle Queen]

Originally Posted by PennyThePenguin

ta daaaaa!!!!!!!!!!!!!!!!!!! calculus... *waits for deb to freak out now*

Eh, I'm not sure it's exactly...calculus. I seem to remember doing some of this stuff in Algebra2 as well. Like I said, it's been a very, very long time. 1980. So that'd be on the order of 25 years. Longer...than most of ya'll have even been around.