Blake is not the "Real No.2" [Archive] - MensTennisForums.com

Blake is not the "Real No.2"

RickDaStick
11-14-2006, 12:07 AM
He is actually the Real No.1. He always beats Nadal who always beats Fed, therefore Blake>Federer.

ServeAlready81
11-14-2006, 12:10 AM
:rolleyes: Are people bored today?

Horatio Caine
11-14-2006, 12:19 AM
No...Ljubo is

Rafa = Fed Killa
11-14-2006, 12:30 AM
:worship:

Not bad for a llubotard :p

neenah
11-14-2006, 01:34 AM
He is actually the Real No.1. He always beats Nadal who always beats Fed, therefore Blake>Federer.

Of course. That's a simple property in math. Blake>Nadal, Nadal>Fed therefore Blake>Fed :rolleyes: :lol:

Jimnik
11-14-2006, 01:39 AM
Of course. That's a simple property in math. Blake>Nadal, Nadal>Fed therefore Blake>Fed :rolleyes: :lol:
Also Roddick>Blake and Blake>Nadal, Nadal>Federer therefore Roddick>Federer. :)

And why stop there? Massu>Roddick,Rod>Blake,Blake>Nadal,Nadal>Fed therefore Massu>Federer.

TMJordan
11-14-2006, 01:41 AM
Also Roddick>Blake and Blake>Nadal, Nadal>Federer therefore Roddick>Federer. :)

And why stop there? Massu>Roddick,Rod>Blake,Blake>Nadal,Nadal>Fed therefore Massu>Federer.

:haha: :haha: :haha: :yeah:

neenah
11-14-2006, 01:46 AM
Also Roddick>Blake and Blake>Nadal, Nadal>Federer therefore Roddick>Federer. :)

And why stop there? Massu>Roddick,Rod>Blake,Blake>Nadal,Nadal>Fed therefore Massu>Federer.

:lol: :lol: :lol: