Fed/Nadal...like Lendl/Becker in 1986? - MensTennisForums.com
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post #1 of 23 (permalink) Old 09-18-2005, 11:09 PM Thread Starter
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Fed/Nadal...like Lendl/Becker in 1986?

I remember in 1986 where Lendl had an incredibly dominant year...almost like Fed's...He won the French and Wimbledon, was in the finals of Wimbledon, and the semis of the Australian...

Becker won Wimbledon over Lendl, and had beaten him two of three times..

Both won a huge number of tourneys, and at the year end championships, Bud Collins stated that while Lendl ended the year at #1, if Becker beat him in the finals, he would BECOME #1...

What if Nadal and Fed both make it to the finals of the year-end championships, and Nadal beat Fed...would the same arguement apply? Any opinions?
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post #2 of 23 (permalink) Old 09-18-2005, 11:46 PM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

No.
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post #3 of 23 (permalink) Old 09-18-2005, 11:50 PM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

Not really, it's a different case. Back then it was much more balanced than now.. not only Roger never loses in finals, but also Nadal can't really beat him off clay (and still, roughly).
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post #4 of 23 (permalink) Old 09-18-2005, 11:56 PM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

Quote:
Originally Posted by sawan66278
Bud Collins stated that while Lendl ended the year at #1, if Becker beat him in the finals, he would BECOME #1...

What if Nadal and Fed both make it to the finals of the year-end championships, and Nadal beat Fed...would the same arguement apply? Any opinions?
Do you mean in the sense of points - if rafa beats Roge then he will get more points to BECOME No.1? Or you mean figurative sense, that it would be like he is No.1 because he beat Roge in the final match of the year?

In the points sense I think it has been shown that unless Roge is retired from all matches until T.M.C and rafa is winning two more T.M.S, then rafa cannot "Become" No.1 in the points race.
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post #5 of 23 (permalink) Old 09-18-2005, 11:57 PM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

Nadal wouldn't have enough points if he did win the Cup. Cup will be indoors and it's faster than China so unless Nadal is in the easy group then it likely won't happen and he won't beat Roger indoors.
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post #6 of 23 (permalink) Old 09-19-2005, 12:50 AM Thread Starter
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Re: Fed/Nadal...like Lendl/Becker in 1986?

I think it would mean #1 in the figurative sense...Nadal would have beaten Roger twice...almost three times!!!! And on one of the biggest stages...I know Roger's record is incredible, but the players in the top ten were light years ahead of the present top ten in achievement and ability...
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post #7 of 23 (permalink) Old 09-19-2005, 01:54 AM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

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Originally Posted by sawan66278
I think it would mean #1 in the figurative sense...Nadal would have beaten Roger twice...almost three times!!!! And on one of the biggest stages...I know Roger's record is incredible, but the players in the top ten were light years ahead of the present top ten in achievement and ability...
The year agassi wins the French open and is finalist at Wimbledon (1999) he is No.1, Pete beat him at the final of the T.M.C but no one said "This means Pete is No.1 for the year" even though he beat No.1 and was H2H for the year 3-1 against andre. andre finish the year No.1 literal and figurative
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post #8 of 23 (permalink) Old 09-19-2005, 03:20 AM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

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Originally Posted by R.Federer
The year agassi wins the French open and is finalist at Wimbledon (1999) he is No.1, Pete beat him at the final of the T.M.C but no one said "This means Pete is No.1 for the year" even though he beat No.1 and was H2H for the year 3-1 against andre. andre finish the year No.1 literal and figurative
Yeah, but I still thought Pete was the better player of the two, and his back injury probably cost him the year end #1 and a real shot at another US Open crown.

So maybe it's not who ends #1, but who is the better player. At this point, I think the results point to Fed being the better player. He's had better results in three of the four GS, and his titles have come in bigger events against better opposition. Who knows what's going to happen until the YEC. But regardless of who ends #1, Fed is in my mind the better player and one match at the YEC is not going to really change that.
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post #9 of 23 (permalink) Old 09-19-2005, 11:21 AM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

Remember 2003?? Even though Roger won the TMC and had more titles than Roddick he "only" finished no. 2 but was by many considered the better player.....

...but I doubt that'll apply for Raffa if he wins TMC as Roger still has a better overall record and so far won one Slam and one TMS more than Raffa.
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post #10 of 23 (permalink) Old 09-19-2005, 11:23 AM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

Quote:
Originally Posted by sawan66278
I remember in 1986 where Lendl had an incredibly dominant year...almost like Fed's...He won the French and Wimbledon, was in the finals of Wimbledon, and the semis of the Australian...

Becker won Wimbledon over Lendl, and had beaten him two of three times..

Both won a huge number of tourneys, and at the year end championships, Bud Collins stated that while Lendl ended the year at #1, if Becker beat him in the finals, he would BECOME #1...

What if Nadal and Fed both make it to the finals of the year-end championships, and Nadal beat Fed...would the same arguement apply? Any opinions?

Federer = Sampras

Nadal = Muster





Now, both Federer and Nadal have 10 Single Titles




ATP Men Single Tiltes (2005):


Hard
Grass
Clay



Roger Federer :

Doha
Rotterdam
Dubai
ATP Masters Series Indian Wells
ATP Masters Series Miami

ATP Masters Series Hamburg
Halle
Wimbledon

ATP Masters Series Cincinnati
US Open






Rafael Nadal :

Costa Do Sauipe
Acapulco
ATP Masters Series Monte Carlo
Barcelona
ATP Masters Series Rome
Roland Garros
Bastad
Stuttgart

ATP Masters Series Canada
Beijing


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post #11 of 23 (permalink) Old 09-19-2005, 11:26 AM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

Cute: huge letters, bright colors.

Anybody else tired of comparisons like Federer=Sampras, Nadal=Muster?

First of all, you can only start comparing when Federer AND Nadal had their career and are enjoying their retirement.
Secondly, Federer is the first Federer and Nadal is the first Nadal.

Last edited by Castafiore; 09-19-2005 at 11:29 AM.
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post #12 of 23 (permalink) Old 09-19-2005, 11:27 AM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

Quote:
Originally Posted by sawan66278
I remember in 1986 where Lendl had an incredibly dominant year...almost like Fed's...He won the French and Wimbledon, was in the finals of Wimbledon, and the semis of the Australian...

Becker won Wimbledon over Lendl, and had beaten him two of three times..

Both won a huge number of tourneys, and at the year end championships, Bud Collins stated that while Lendl ended the year at #1, if Becker beat him in the finals, he would BECOME #1...

What if Nadal and Fed both make it to the finals of the year-end championships, and Nadal beat Fed...would the same arguement apply? Any opinions?




Lendl - Roland Garros, US Open

Becker - Wimbledon

Also, Australian Open was not held in 1986



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post #13 of 23 (permalink) Old 09-19-2005, 11:47 AM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

Nadal's result this year in slams were not good enough to be number one. Outside RG : 4th round (or is it quarter?), 2nd round, 3rd round.
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post #14 of 23 (permalink) Old 09-19-2005, 01:41 PM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

this a stupid question. roger has 2 slams this year, nadal one with shit results in the others. roger is no1 by a mile, hes won bigger and better tournies than nadal, so to say if nadal beats roger in the cup he would be the best in world is just utter shite.
nadals time will come but it aint now.

131 and proud
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post #15 of 23 (permalink) Old 09-19-2005, 01:42 PM
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Re: Fed/Nadal...like Lendl/Becker in 1986?

Quote:
Originally Posted by vincayou
Nadal's result this year in slams were not good enough to be number one. Outside RG : 4th round (or is it quarter?), 2nd round, 3rd round.
4th

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